The Least Number Which When Divided By 4, 6, 8, 12 And 16 Leaves A Re

1.	The Least Number Which When Divided By 4, 6, 8, 12 And 16 Leaves A Remainder Of 2 In Each Case Is?
Answer» Let’s find a number which is COMPLETELY divisible by 4, 6, 8, 12 and 16. To find such number, we NEED to find the LCM of all these numbers LCM of (4,6) , 8 , 12 , 16 = 12 , 8 , 12 , 16 = LCM of (12 , 8) , LCM of (12 , 16) = 24 , 48 = LCM of (24 , 48) = 48 HENCE 48 + 2 ie 50 will leave a remainder of 2 if divided by any of the following numbers : 4, 6, 8, 12 and 16 Let’s find a number which is completely divisible by 4, 6, 8, 12 and 16. To find such number, we need to find the LCM of all these numbers LCM of (4,6) , 8 , 12 , 16 = 12 , 8 , 12 , 16 = LCM of (12 , 8) , LCM of (12 , 16) = 24 , 48 = LCM of (24 , 48) = 48 Hence 48 + 2 ie 50 will leave a remainder of 2 if divided by any of the following numbers : 4, 6, 8, 12 and 16

The Least Number Which When Divided By 4, 6, 8, 12 And 16 Leaves A Remainder Of 2 In Each Case Is?

Answer»

Let’s find a number which is COMPLETELY divisible by 4, 6, 8, 12 and 16.

To find such number, we NEED to find the LCM of all these numbers

LCM of (4,6) , 8 , 12 , 16

= 12 , 8 , 12 , 16

= LCM of (12 , 8) , LCM of (12 , 16)

= 24 , 48

= LCM of (24 , 48)

= 48

HENCE 48 + 2 ie 50 will leave a remainder of 2 if divided by any of the following numbers : 4, 6, 8, 12 and 16

Let’s find a number which is completely divisible by 4, 6, 8, 12 and 16.