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Thereadingof voltmeter in the circuit shown is40Ω60 ΩV,40 Ω(1) 2.25 V(2) 3.25 V(3) 4.25 V(4) 6.25 v |
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Answer» the voltmeter resistance is in parallel to 60Ω , that is 40Ω , so they add up to give req = 60*40/(60+40) = 24Ω now , total resistance is 40+24 = 64Ω so, current in the circuit is 6/64 = 3/32A now voltage around voltmeter is 3/32*(24) = 9/4 = 2.25V option 1 |
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