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Three capacitors each of capacitance `C` and of breakdown voltage `V` are joined in series. The capacitance and breakdown voltage of the combination will beA. `(C )/(3), (V)/(3)`B. `3C, (V)/(3)`C. `(C )/(3), 3V`D. `3C, 3V` |
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Answer» Correct Answer - C In series combination charge on each plate of each capacitor has the same magnitude. The potential difference is distributed inversely in the ratio of capacitors, i.e., `V = V_(1) + V_(2) + V_(3)`.. Here, `V = 3V` The equivalent capacitance `C_(s)` is given by `(1)/(C_(s)) = (1)/(C_(1))+(1)/(C_(2))+(1)/(C_(3))+..` `C_(s) = (C )/(3)` |
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