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Three capacitors of `2 muF, 3 muF` and `6 muF` are joined in series and the combination is charged by means of a `24` volt battery. The potential difference between the plates of the `6 muF` capacitor isA. `4` voltB. `6` voltC. `8` voltD. `10` volt |
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Answer» Correct Answer - A `(1)/(C_(eq)) = (1)/(2) + (1)/(3) + (1)/(6) rArr C_(eq) = 1muF` Total charge `Q = C_(eq).V = 1 xx 24 = 24 muC` Potential diff. across `6muF` capacitor `= (24)/(6) = 4` volt |
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