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Three charge `+q, -q`, and `+2q` are placed at the vertices of a right angled triangle (isosceles triangle)as shown. The net electrostatic energy of the configuration is: A. `-(kq^(2))/(a) (sqrt(2 + 1))`B. `(Kq^(2))/(a)(sqrt(2) + 1)`C. `-(Kq^(2))/(a) (sqrt(2) -1)`D. None of these |
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Answer» Correct Answer - C `U = (Kq^(2))/(a) (-1+2-(2)/(sqrt(2)))` `= (Kq^(2))/(a) (1-sqrt(2)) rArr U = - (kq^(2))/(a)(sqrt(2)-1)` |
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