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Three forces acting on a body are shown in figure. To have the resultant force only along the y-directon, the magnitude of the minimum additional force needed si A. 0.5NB. 1.5NC. `(sqrt(3))/(4)N`D. `sqrt(3)N` |
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Answer» Correct Answer - A (a) Minimum additional force needed `F=-(F_("resultant"))_(x)` `F_("resultant")=[(4-2)(cos 30 jhatj-sin 30 hati)+( cos 60 hati +sin 60 hatj)]` `=[2((sqrt(3))/(2)hatj-(1)/(2)hati)+((1)/(2) hati+(sqrt(3))/(2) hatj)]` `=[(sqrt(3)+(sqrt(3))/(2))hatj+(- hati+(hati)/(2))]` `=[-(1)/(2)hati+(3sqrt(3))/(2) hatj]=-(1)/(2)+(3sqrt(3))/(2)hatj` `implies F_(x)=(-( hati)/(2))` Hence, `|F|=0.5N` |
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