Three houses are available in a locality. Three persons apply for the

1.	Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three apply for the same house is1. 8 / 92. 7 / 93. 2 / 94. 1 / 9
Answer» Correct Answer - Option 4 : 1 / 9 Concept: P(E) = Probability of an event E = \(\rm \frac{\text{Favourable outcome}}{\text{Total outcome }} \) Number of ways of choosing m objects by n people with no restriction = \(\rm m^{n}\) Calculation: Given number of house (m) = 3 number of people applying for house(n) = 3 total number of way three people can apply for house = \(3^{3}\) = 27 Number of way in which all people apply for same house = 3 P(all three applying for same house) = \(\frac{3}{27}\) = \(\frac{1}{9}\)

Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three apply for the same house is1. 8 / 92. 7 / 93. 2 / 94. 1 / 9

Answer» Correct Answer - Option 4 : 1 / 9

Concept:

P(E) = Probability of an event E = \(\rm \frac{\text{Favourable outcome}}{\text{Total outcome }} \)

Number of ways of choosing m objects by n people with no restriction = \(\rm m^{n}\)

Calculation:

Given

number of house (m) = 3

number of people applying for house(n) = 3

total number of way three people can apply for house = \(3^{3}\) = 27

Number of way in which all people apply for same house = 3

P(all three applying for same house) = \(\frac{3}{27}\) = \(\frac{1}{9}\)

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