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Three inductances are connected as shown belowAssuming no coupling. the resultant inductance will be-(LI = 0.75 H. L2 = L3 0.5 H)(a) 0.25 H(b) 0.75 H(c) 0:01 H(d) 1 HL2Liし3 |
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Answer» Here, L2 and L3 are in parallel so the equivalent inductance will be Leq = L2*L3/L2+L3 = 0.5/2 = 0.25H and it is in series with L1 so total inductance will be L1+ Leq = 0.75+0.25 = 1H option d. |
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