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Three liquids of densities d, 2d and 3d are mixedin equal proportions of weights. The relativedensity of the mixture is |
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Answer» Without specifying the proportions, all we know is that it will be somewhere between 1d and 3d. If, at a guess, the proportions are supposed to be equal in volume, then it will be: (1d + 2d + 3d) / 3 = 6d / 3 = 2d If they are supposed to be equal in mass, then it would be: 1 + 1 + 1 / (1/1d + 1/2d + 1/3d) = 3 / (11/6d) = 18d/11 |
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