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Three masses of 5 kg ,3kg,2kg are placed on a smooth horizontal surface .when a force of 100 Neuton is applied on it find acceleration of of system .tension t1 and t2 |
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Answer»
Answer: i)a=10m/s T1=80 T2=60 Explanation: i)We KNOW that F=(all masses)a =>100=10a =>10a=100 =>a=100/10 a=10m/s =>a=10m/s ii)t1 and t2 T1=F-2a =>100-2(10) =100-20 =80 T2=F-2a =>80-2(10) =80-20
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