InterviewSolution
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InterviewSolution
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Three particles A, B and C each of mass m arelying at the corners of an equilateral triangle of sideL. If the particle A is released keeping the particlesB and C fixed, the magnitude of instantaneousacceleration of A isAgmL m |
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Answer» The gravitational force from Point A to point B: F₁ = G(m)(m)/L² = Gm²/L² The gravitational force from Point A to point C: F₂ = G(m)(m)/L² = Gm²/L² Now we will look at the magnitudes of F₁ and F₂ Let F₁ = F₂ = F Angle is 60° which is between F₁ and F₂ Now we will calculate the net force on the particle A: F base net = √F² + F² + 2(F) (F) cos 60° = √3F² = √3F Now we will calculate the acceleration for the particle A: a = F base net/ m = √3F/m = √3/m (Gm²/L²) = √3Gm/ L² |
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