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Three particles each of mass m are placed at the three corners of an equilateral triangle. The centre of the triangle is at adistance x from either corner If a mass M be placed at the centre, what will be the net gravitational force on it(A) Zero(B) 3GMm i x(D) GMmix36 |
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Answer» The gravitational force on M due to the three masses will form a system of concurrent forces of equal magnitude GmM/(x^2). Since these forces are at an angle of 120 degrees with respect to each other, the net resultant of force will be zero. Hence, Option A is correct. |
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