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Three resistance are joined together as sidesof triangle ABC as shown in the figure. Whatis the quivalent resistance across B and C ?6022(a) 502(b) 642(c) 322(d) 200210092 |
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Answer» option D is the correct answer Option D is the correct answer. firstly, according to the question's given condition 40ohm and 60 ohm are series so, R = R(ac) + R (cb) R = 100 + 60 R = 160 ohm ------------( 1 ) this R is parallel to 40 ohm, therefore, 1 / R = 1 / 40 + 1 / 160 1 / R = 5 / 160 R = 160/5 R = 32 ohm. The correct answer is option (d)200 ohm. R=R1+R2=40+60=200;. 1/R=1/R1 + 1/R2=1/100+1/100=1+1/100=2/100=1/50 |
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