1.

Three resistance are joined together as sidesof triangle ABC as shown in the figure. Whatis the quivalent resistance across B and C ?6022(a) 502(b) 642(c) 322(d) 200210092

Answer»

option D is the correct answer

Option D is the correct answer.

firstly, according to the question's given condition

40ohm and 60 ohm are series so,

R = R(ac) + R (cb)

R = 100 + 60

R = 160 ohm ------------( 1 )

this R is parallel to 40 ohm,

therefore,

1 / R = 1 / 40 + 1 / 160

1 / R = 5 / 160

R = 160/5

R = 32 ohm.

The correct answer is option (d)200 ohm.

R=R1+R2=40+60=200;. 1/R=1/R1 + 1/R2=1/100+1/100=1+1/100=2/100=1/50



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