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Three rods of identical cross-sectional area and made from the same metal form the sides of an isosceles triangle ABC right angled at B as shown in the figure. The points A and B are maintained at temperature T and `(sqrt2)T` respectively in the steady state. Assuming that only heat conduction takes place, temperature of point C will be A. `T/((sqrt2)-1)`B. `T/((sqrt2)+1)`C. `(3T)/((sqrt 2)+1)`D. `T/((sqrt3)(sqrt2 -1))` |
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Answer» Correct Answer - C `H_1 = H_2` `:. (sqrt(2)T -T_C)/((l//KA)) = (T_C-T)/((sqrt(2)l//KA)` Solving we get, `T_C = (3T)/((sqrt2) +1)`. |
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