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Two identical conducting rods are first connected independently to two vessels, one containing water at `100^@C` and the other containing ice at `0^@C`. In the second case, the rods are joined end to end and connected to the same vessels. Let `q_1 and q_2` gram per second be the rate of melting of ice in the two cases respectively. The ratio `q_1/q_2` is (a) `1/2` (b)`2/1` (c)`4/1` (d)`1/4` |
Answer» Correct Answer - A<br>(c) `(dQ)/(dt) = L(dm)/(dt) or ("Temperature difference")/("Thermal resistance") = L ((dm)/(dt))`<br> or `(dm)/(dt) prop 1/("Thermal resistance" ) rArr q prop 1/R`<br> In the first case rods are in parallel and thermal resistance is `R/2` while in second case rods are in series and thermal resistance is 2R.<br> `(q_1/q_2) = (2R)/(R//2) = 4/1` | |