Three years ago, the population of a town was 50000. If the annual inc

1.	Three years ago, the population of a town was 50000. If the annual increase during three successive years be at the rate of 5%, 4% and 3% respectively, what is its present population?
Answer» Population of a town, P = 50000 Interest rate for 1^st year, p = 5% Interest rate for 2^nd year, q = 4% Interest rate for 3^rd year, r = 3% Time, n = 3 years Now, Present population = P × (1 + p/100) × (1 + q/100) × (1 + r/100) = 50000 × (1 + 5/100) × (1 + 4/100) × (1 + 3/100) = 50000 × (1 + 1/20) × (1 + 1/25) × (1 + 3/100) = 50000 × 21/20 × 26/25 × 103/100 = 50 × 21/2 × 26/25 × 103 = 1 × 21 × 26 × 103 = 56238 ∴ Present population of a town is 56238.

Three years ago, the population of a town was 50000. If the annual increase during three successive years be at the rate of 5%, 4% and 3% respectively, what is its present population?

Answer»

Population of a town, P = 50000

Interest rate for 1^st year, p = 5%

Interest rate for 2^nd year, q = 4%

Interest rate for 3^rd year, r = 3%

Time, n = 3 years

Now,

Present population = P × (1 + p/100) × (1 + q/100) × (1 + r/100)

= 50000 × (1 + 5/100) × (1 + 4/100) × (1 + 3/100)

= 50000 × (1 + 1/20) × (1 + 1/25) × (1 + 3/100)

= 50000 × 21/20 × 26/25 × 103/100

= 50 × 21/2 × 26/25 × 103 = 1 × 21 × 26 × 103

= 56238

∴ Present population of a town is 56238.