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Time taken by a 836 W heater to heat one litre of water from `10^@C to 40^@C` isA. `50 s`B. `100s`C. `150s`D. `200s`

Answer» Correct Answer - C
Let time taken in boiling the water by the heater is t sec. Then
`Q = ms Delta T`
`(836)/(4.2) t = 1 xx 1000 (40^(@) - 10^(@))`
`(836) /(4.2) t = 1000 xx 30 rArr t = (100 xx 30 xx 4.2)/(836) = 150 sec`


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