InterviewSolution
 Saved Bookmarks
    				| 1. | 
                                    To increase currant sensitivity of moving cell galvanometer by 50%, itsresistance is increased so that new resistance becomes twice its initialresistance. By what factor does its voltage sensitivity changes | 
                            
| 
                                   
Answer»  Resistance formulae : R = V/I Where : R = the resistance V = voltage I = current If the I is increased by 50% then the new I = 1.5I The new resistance becomes : 2R 2R = 1.5I /V V = 1.5I/2R V = 0.75(I/R) The V changes by 0.25 The percentage change = 25%  | 
                            |