1.

To increase currant sensitivity of moving cell galvanometer by 50%, itsresistance is increased so that new resistance becomes twice its initialresistance. By what factor does its voltage sensitivity changes

Answer»

Resistance formulae :

R = V/I

Where :

R = the resistance

V = voltage

I = current

If the I is increased by 50% then the new I = 1.5I

The new resistance becomes :

2R

2R = 1.5I /V

V = 1.5I/2R

V = 0.75(I/R)

The V changes by 0.25

The percentage change = 25%



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