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to maintain a rotation at a uniform angular speed of 200m/s, an engine needs to transmit a torque of 180 N.m, what is the power of the engine required? |
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Answer» Angular speed of the rotor, ω = 200 rad/sTorque required, τ = 180 NmThe power of the rotor (P) is related to torque and angular speed by the relation:P= τω= 180 × 200 = 36 × 103= 36 kWHence, the power required by the engine is 36 kW. |
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