1.

To produce characteristic `X` - rays using a Tungsten target in an x - ray generator , the accelerating should be greater then ……. Volts and the energy of the characteristion is …… eV . (The binding energy of the intermost electron in Tungsten is - 40keV).

Answer» Correct Answer - C
For minimum accelerating voltage , the electron should jump
from `n = 2`to`n = 1leval`
for characterintic X - rays
`(1)/(lambda) = R_(a)(L-1)^(2) [1 - (1)/(n^(2))] = (E)/ (hc)
( E_(1))/(hc) = R_(a) (Z - 1)^(2)[1 -(1)/(2^(2)) ] ` …..(i)
The binding energy of innermost eletron ` = 40 keV` `
`:.` lonisation potential of tungsten ` = 40 kV = 40 xx 10^(2) V`
`rArr (E_(2))/(hc) = R_(a) (Z - 1)^(2)[1 -(1)/(2^(2)) ] ` ....(ii)
` (E_(1))/(E_(2)) = [[1 - (1)/(2^(2))]]/([1 - (1)/(oo^(2)]]`
`rArr E_(1) = (3)/(4) E_(2) = (3)/(4) xx 40000 eV = 30000 eV`
`:. ` Minimum accelerating vollage
`V_(min) = (E_(1))/(e) = 30000 V `


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