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To what potential must a insulated sphere of radius 10 cm be charged so that the surface density of charge is equal to 1μC/m². |
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Answer»
Here V=?,r=14cm=14×10−2m σ=1μCm−2=10−6Cm−2 V=q4π∈0r=14π∈0(σ.4πr2r) =14π∈0(4πrσ) =9×109×4×227×14×10−2×10−6 V=15840v
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