To what series does the speciral lines of atomic hydrogen belong if its wavelength is equal to the difference between the wavenumber of the folowing two lines of the Balmer series `486.1` and `419.2 nm`? What is the waveeath of thqat line ?

To what series does the speciral lines of atomic hydrogen belong if it

1.	To what series does the speciral lines of atomic hydrogen belong if its wavelength is equal to the difference between the wavenumber of the folowing two lines of the Balmer series `486.1` and `419.2 nm`? What is the waveeath of thqat line ?
Answer» Given `lambda_(1) = 486.1 xx 10^(-9)m = 486.1 xx 10^(-7) cm` `lambda_(2) = 410.2 xx 10^(-9)m = 410.2 xx 10^(-7) cm` ` bar v = bar v_(2) - barv _(1)` `= (1)/(lambda_(2)) - (1)/(lambda_(1))` `= R_(H) [(1)/(2^(2)) - (1)/(n_(2)^(2))] - R_(H) [(1)/(2^(2)) - (1)/(n_(1)^(2))]` `bar v = R_(H)[1/n_(1)^(2)-1/n_(1)^(2)]`........(i) For 1 case of balance series `(1)/(lambda_(1)) = R_(H) [(1)/(2^(2)) - (1)/(n_(1)^(2))] = 109678 [(1)/(2^(2)) - (1)/(n_(1)^(2))]` or `(1)/(4186.1 xx 10^(-5)) = 109678[(1)/(2^(2)) - (1)/(n_(1)^(2))]` `:. n_(1) = 4` For II case of Balmer series `(1)/(lambda) = (1)/(410.2 xx 10^(-7)) = 10978 [(1)/(2^(2)) - (1)/(n_(2)^(2))]` `:. n_(2) = 6` THus giuven transition occurs from sixth level to four level .Also equation (i) `bar v = (1)/(lambda) = 109678 [(1)/(4^(2)) - (1)/(6^(2))]` `:. lambda = 2.63 xx 10^(-4) cm `

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To what series does the speciral lines of atomic hydrogen belong if its wavelength is equal to the difference between the wavenumber of the folowing two lines of the Balmer series `486.1` and `419.2 nm`? What is the waveeath of thqat line ?

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