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TOBUSUJ WWhen 20 J of work was done on a gas, 40J of heat energy was released. If the initial internal energyof the gas was 700, what is the final internal energy?D 50J2) 60 J4) 11033) 90 ) |
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Answer» According to first law of thermodynamics, Q = dU + W Q= - 40J (heat released by gas) W= - 20J (work done on gas) Hence, - 40 = dU - 20 dU = - 20 J Final internal energy - Initial internal energy = - 20 Therefore, Final Internal energy = 70 - 20= 50 J (1) is correct option |
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