1.

TOBUSUJ WWhen 20 J of work was done on a gas, 40J of heat energy was released. If the initial internal energyof the gas was 700, what is the final internal energy?D 50J2) 60 J4) 11033) 90 )

Answer»

According to first law of thermodynamics,

Q = dU + W

Q= - 40J (heat released by gas)

W= - 20J (work done on gas)

Hence, - 40 = dU - 20

dU = - 20 J

Final internal energy - Initial internal energy = - 20

Therefore, Final Internal energy = 70 - 20= 50 J

(1) is correct option



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