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Topic :- Kinetic theory of gasesShow your working :) |
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Answer» ☆♧Answered by Rohith kumar maths dude :-♧♧Given:-PV diagram of two different masses m1 and m2.♧♧To prove :-State WHEATHER m1 >m2 or m2 >m1♧♧Proof:-Here By USING ideal gas equation in both of the cases .First we take, ♧♧Assumption :- both gases are identical only.●And taking MOLAR mass in each cases is M.Let take formula of ideal gas equation: -♧(i) Case:-PV=n1RTPV=m1 (RT/M) -----(i)♧(ii) Case:-PV=n2RT PV= m2 (RT/M) ------(ii)♧♧♧Let,v=vnot from the graph P1 and P2 are pressures And P2>P1 ----(III).♧♧P1V not= m1(RT/M)♧♧P1= m1/V not (RT/M)♡♡P2V not= m2 (RT/M)♡♡P2= m2/V not (RT/M)♧♧Now solving , ♧♧P2>P1Applying the P1 and P2 values,=m1/V not (RT/M) > m2/V not (RT/M)♧From this we get ,= m1 > m2♧☆Hope it helps U @Mystified boy (Apprentice moderator) ☆☆Thank you for good question . |
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