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Train starts from rest and accelerates at a rate of 1..m/s. Calculate the velocity in km/hr at the endof 375m |
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Answer» Answer: 98.6 kmph Explanation: v² - u² = 2aS v = sqrt(u² + 2aS) = sqrt(0² + (2 × 1 × 375)) = sqrt(750) m/s = 27.4 m/s = 27.4 × 18/5 kmph = 98.6 kmph |
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