1.

Train starts from rest and accelerates at a rate of 1..m/s. Calculate the velocity in km/hr at the endof 375m​

Answer»

Answer:

98.6 kmph

Explanation:

USE EQUATION of MOTION

v² - u² = 2aS

v = sqrt(u² + 2aS)

= sqrt(0² + (2 × 1 × 375))

= sqrt(750) m/s

= 27.4 m/s

= 27.4 × 18/5 kmph

= 98.6 kmph



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