InterviewSolution
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InterviewSolution
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Twelve Men Can Complete A Work In 8 Days. Three Days After They Started The Work, 3 More Men Joined Them. In How Many Days Will All Of Them Together Complete Remaining Work? |
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Answer» 1 man’s ONE DAY’s work = 1/96 12 men’s 3 day’s work = (3 x 1/8) = 3/8 REMAINING work = (1 – 3/8) = 5/8 15 men’s 1 day’s work = 15/96 Now 15/96 work is done by them in 1day Therefore 5/8 work will be done by them in (96/15 x 5/8) i.e., 4 days. 1 man’s one day’s work = 1/96 12 men’s 3 day’s work = (3 x 1/8) = 3/8 Remaining work = (1 – 3/8) = 5/8 15 men’s 1 day’s work = 15/96 Now 15/96 work is done by them in 1day Therefore 5/8 work will be done by them in (96/15 x 5/8) i.e., 4 days. |
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