Two 1 Coulomb charges are kept at 1m distance in air medium. Force of attraction or repulsion between them will be ________(a) 9*10^9 N(b) 1 dyne(c) 1 N(d) 3*10^3 NThe question was asked by my college professor while I was bunking the class.My doubt stems from Coulomb’s Law in section Charges and Fields of Physics – Class 12

Two 1 Coulomb charges are kept at 1m distance in air medium. Force of

1.	Two 1 Coulomb charges are kept at 1m distance in air medium. Force of attraction or repulsion between them will be ________(a) 910^9 N(b) 1 dyne(c) 1 N(d) 310^3 NThe question was asked by my college professor while I was bunking the class.My doubt stems from Coulomb’s Law in section Charges and Fields of Physics – Class 12
Answer» RIGHT option is (a) 910^9 N The best explanation: According to Coulomb’s Law, F=\(\FRAC {1}{4\pi \varepsilon_o }\frac {q_1q_2}{r^2}\). And \(\frac {1}{4\pi \varepsilon_o}\) = 910^9N in the SI system. In this case, q1=q2=1C and r=1m. Now substituting the VALUES we get F=910^9N. Similarly, the electric field at a distance of 1m from a 1C CHARGE is 9*10^9N/C.

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