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Two adjacent sides of a parallelogram ABCD are `2hati+4hatj -5 hatkand hati+2hatj+3hatk`. Then the value of `|vec(AC)xxvec(BD)|` isA. `20sqrt5`B. `22sqrt5`C. `24sqrt5`D. `26sqrt5` |
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Answer» Correct Answer - b `|vec(AC) xx vec(BD)|=2 |vec(AB)xxvec(AD)|` `2|{:(hati,hatj,hatk),(2,4,-5),(1,2,3):}|` `|2[hati(12+10)-hatj (6+5)+hatk (4-4)]|` `|2[22hati -11 hatj]|` `22 |[2hati - hatj]|` `22xx sqrt5` |
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