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Two arithmetic progressions have the same common difference. The difference between their 100th terms is 100, what is the difference between their 1000th terms? |
Answer» Let the two A.Ps be A.P1 and A.P2 For A.P1 the first term = a and the common difference = d And for A.P2 the first term = b and the common difference = d So, from the question we have a100 – b100 = 100 (a + 99d) – (b + 99d) = 100 a – b = 100 Now, the difference between their 1000th terms is, (a + 999d) – (b + 999d) = a – b = 100 Therefore, the difference between their 1000th terms is also 100. |
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