1.

Two Beakers Are On The Table. The Capacity Of The First Beaker Is X Liters And That Of The Second Beaker Is 2x Liters. Two Thirds Of The First Beaker And One Fourth Of The Second Beaker Is Filled With Wine. The Remaining Space Is Filled With Water. If The Content In Both The Beakers Are Mixed In A Large Beaker Of Volume 3x Liters, What Is The Proportion Of Wine In The Beaker ?

Answer»

CAPACITY of beakers x,2x,3x

2/3(x)+1/4(2x)=7x/6

WINE PROPORTION is =7x/(6*3x)=7/18

capacity of beakers x,2x,3x

2/3(x)+1/4(2x)=7x/6

wine proportion is =7x/(6*3x)=7/18



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