1.

Two Liquids Are Mixed In The Proportion Of 3:2 And The Mixture Is Sold At $11 Per Liter At A 10% Profit. If The First Liquid Costs $2 More Per Liter Than The Second, What Does It Cost Per Liter ?

Answer»

Given two liquids proportion as 3:2

from the MIXTURES

SUPPOSE second LIQUID cost = $x, then FIRST liquid = $(x+2)

(x-10)/(10-x-2) = 3/2

2x-20 = 24-3x

5x = 44

x=8.8

so first liquid cost is x+2 = 8.80+2 = $10.80

Given two liquids proportion as 3:2

from the mixtures: 

Suppose second liquid cost = $x, then first liquid = $(x+2)

(x-10)/(10-x-2) = 3/2

2x-20 = 24-3x

5x = 44

x=8.8

so first liquid cost is x+2 = 8.80+2 = $10.80



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