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Two Liquids Are Mixed In The Proportion Of 3:2 And The Mixture Is Sold At $11 Per Liter At A 10% Profit. If The First Liquid Costs $2 More Per Liter Than The Second, What Does It Cost Per Liter ? |
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Answer» Given two liquids proportion as 3:2 from the MIXTURES: SUPPOSE second LIQUID cost = $x, then FIRST liquid = $(x+2) (x-10)/(10-x-2) = 3/2 2x-20 = 24-3x 5x = 44 x=8.8 so first liquid cost is x+2 = 8.80+2 = $10.80 Given two liquids proportion as 3:2 from the mixtures: Suppose second liquid cost = $x, then first liquid = $(x+2) (x-10)/(10-x-2) = 3/2 2x-20 = 24-3x 5x = 44 x=8.8 so first liquid cost is x+2 = 8.80+2 = $10.80 |
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