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Two block of masses `2kg` and `4kg` are released from rest over a smooth inclined place of inclination `30^(@)` as shown in figure what is the normal force between the two blocks? |
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Answer» Since surface is smooth acceleration of both is `g sin theta = 10 sin 30^(@) = 5 m//s^(2)` down the plane. The component of `mg` down the plane `(= mg sin theta)` provides this acceleration. So normal reation will be zero. |
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