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Two blocks A and B each of mass m are placed on a smooth horizontal surface. Two horizontal force F and 2F are applied on blocks A and B, respectively, as shown in fig. Block A does not slide on block B. Then then the normal reaction acting between the two blocks is (assume no friction between the blocks) A. FB. `(F)/(2)`C. `(F)/(sqrt(3))`D. 3F |
Answer» Correct Answer - D (d) `a=(2F-F)/(2m)=(F)/(2m)`( toward left) Writing equation of right hand side block, `2F-N sin 30^(@)=ma=(F)/(2)` `(N)/(2)=2F-(F)/(2)=(3F)/(2) implies N=3F` |
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