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Two blocks are in contact on a frictionless table. One has mass m and the other 2m. A force F is applied on 2m as shown in the figure. Now the same force F is applied from the right on m. In the two cases the ratio of force of contact between the two blocks will be A. sameB. `1:2`C. `2:1`D. `1:3` |
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Answer» Correct Answer - B (b) Acceleration in both the case will be same.l `N_(1)=ma " but " N_(2)=(2m)a` `therefore " " (N_(1))/(N_(2))=(1)/(2)` |
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