1.

. Two bodies A and B of mass 150 g and 250 grespectively are approaching each other. Bothparticles have a speed of 3 m/s. Find the magnitudeof the total linear momentum of the system of thetwo particles.

Answer»

Mass of body A, ma= 150 g = 0.15 kg

Mass of body B, mb= 250 g = 0.25 kg

Both the bodies are moving towards each other. Let the direction of B be taken as positive. Then the direction of A will be considered negative.

Velocity of A, va= - 3 m/s

Velocity of B, vb= 3 m/s

Now, total momentum of the system,

P = mava+ mbvb

=> P = (0.15)(-3) + (0.25)(3)

=> P = -0.45 + 0.75

=> P = 0.30 Ns



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