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Two bodies A and N having masses m and 2m respectively are kept at distance d apart a small particle is to be placed so that the net gravity force on it,due to the bodies A and B is zero it's distance for Ma should be

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Question in correct form is:Two bodies A and B of masses m and 2m respectively are kept a distance d apart. Where a small particle be placed so that the net gravitational force on it due to the bodies A and B is 0.

Answer:Net gravitational force will be zero towards less massive body.Let,The mass of small particle which is being placed is m₀Distance between m₀ and m = xThen, distance between m₀ and 2m = d - x

Force due to m on m₀ = Force due to 2m on m₀Gmm₀/x^2 = G*(2m) * (m₀) / (d - x)^21/√2 = x / (d - x)x√2 = d - xx = d / 2.414x = 0.414 d

The small particle should be kept at a distance 0.414d from A.



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