Two bodies at different temperatures T_1 and T_2 , if brought in thermal contact do not necessarily settle to the mean temperature (T_1 + T_2)//2Explain.

Two bodies at different temperatures T_1 and T_2 , if brought in therm

1.	Two bodies at different temperatures T_1 and T_2 , if brought in thermal contact do not necessarily settle to the mean temperature (T_1 + T_2)//2Explain.
Answer» Solution :Heat flows from higher temperature to LOWER temperature until the temperature BECOME equal. Two BODIES `m_1 = "mass of 'A'"T_1""T_2m_2` = mass of 'B' `c_1` = specific heat of A `"" c_2` = Sepecific heat of B Let `T_1 gt T_2` Heat will be lost by ‘A’ and gained by ‘B’ ACCORDING to principle of caloriemetry, Heat lost = Heat gained Let their common temperature attained be ‘T’, `m_1c_1(T_1-T)=m_2c_2(T-T_2)` `m_1c_1T_1-m_1c_1T = m_2c_2T-m_2c_2T_2` `m_1c_1T_1+m_1c_1T_2 = (m_1c_1+m_2c_2)T` `T = (m_1c_1T_1+m_2c_2T_2)/((m_1c_1+m_2c_2))` It is possible only, If `m_1=m_2=m,C_1=C_2=C,` `T=(T_1+T_2)/2`