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Two bodies of masses 10 kg and 20 kg respectively kept on a smooth horizontal surface are tied to the ends of a light string A horizontal force F = 600 N is applied to (i) A and (ii) B along the direction of string. What is the tension in the string in each case ? |
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Answer» Acceleration = 600 N / 10 kg + 20 kg = 20 `ms^(-2)` (i) When force is applied on 10 kg mass 600 - T = `10 xx 20` or T = 400 N (ii) When force is applied on 20 kg mass, 600 - T = `20 xx 20` or T = 200 N |
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