Two bodies of masses 5kg and 15kg are separated by a distance of 5m.Ca

1.	Two bodies of masses 5kg and 15kg are separated by a distance of 5m.Calculate the gravitational force between them.
Answer» ANSWER: $\textsf{<klux>FORCE</klux> between the <klux>TWO</klux> bodies} \ \sf =2 \times 10^{-10} \ N$ GIVEN: Two bodies of MASSES 5 kg and 15 kg are SEPARATED by a distance of 5 m. TO FIND: Gavitational force between the two bodies. EXPLANATION: $\boxed{ \bold{ \gray{ \large{F=\dfrac{Gm_1m_2}{d^2}}}}}$ Here G is the universal gravitational constant. $\sf G = 6.673 \times 10^{-11}\ Nm^2kg^{-2}$ $\sf m_1 = 5 \ kg$ $\sf m_2 = 15\ kg$ $\sf d = 5\ m$ $\sf F =\dfrac{6.673 \times 10^{-11} \times 5(15)}{5^2}$ $\sf F =6.673 \times 10^{-11} \times 3$ $\sf F =20 \times 10^{-11}$ $\sf F =2 \times 10^{-10} \ N$ Hence the force between the two bodies = $\bf 2 \times 10^{-10} \ N$ NEWTON's LAW OF GRAVAITATION: Newton's law of gravitation states that every object in the universe attracts every other object with a force that is directly proportional to the product of their massess and inversely proportinal to the square of the distance between them. Diagram: $\setlength{\unitlength}{1cm}\begin{picture}(0,0) \thicklines\put( 0, 0){\line(1,0){4}}\put( - 0.6, - 0.1){$\bf m_1$}\put(4.1, - 0.1){$\bf m_2$}\multiput(0, 0)(4, 0){2}{\circle{0.1}} }\put( 0, - 0.1){$\underbrace{ \qquad\qquad\qquad\qquad\qquad \: \: \: \: \: \: }$}\put(1.85, - 0.65){$\bf d$}\end{picture}$ Derivation:* $\sf F \propto m_1 m_2$ $\sf F \propto \dfrac{1}{d^2}$ $\sf F \propto \dfrac{m_1 m_2}{d^2}$ $\sf F = \dfrac{Gm_1 m_2}{d^2}$ Here G is the constant of propotionality and is called universal gravitational constant.

Two bodies of masses 5kg and 15kg are separated by a distance of 5m.Calculate the gravitational force between them.

Answer»

ANSWER:

$\textsf{<klux>FORCE</klux> between the <klux>TWO</klux> bodies} \ \sf =2 \times 10^{-10} \ N$

GIVEN:

Two bodies of MASSES 5 kg and 15 kg are SEPARATED by a distance of 5 m.

TO FIND:

Gavitational force between the two bodies.

EXPLANATION:

$\boxed{ \bold{ \gray{ \large{F=\dfrac{Gm_1m_2}{d^2}}}}}$

Here G is the universal gravitational constant.

$\sf G = 6.673 \times 10^{-11}\ Nm^2kg^{-2}$

$\sf m_1 = 5 \ kg$

$\sf m_2 = 15\ kg$

$\sf d = 5\ m$

$\sf F =\dfrac{6.673 \times 10^{-11} \times 5(15)}{5^2}$

$\sf F =6.673 \times 10^{-11} \times 3$

$\sf F =20 \times 10^{-11}$

$\sf F =2 \times 10^{-10} \ N$

Hence the force between the two bodies = $\bf 2 \times 10^{-10} \ N$

NEWTON's LAW OF GRAVAITATION:

Newton's law of gravitation states that every object in the universe attracts every other object with a force that is directly proportional to the product of their massess and inversely proportinal to the square of the distance between them.

Diagram:

$\setlength{\unitlength}{1cm}\begin{picture}(0,0) \thicklines\put( 0, 0){\line(1,0){4}}\put( - 0.6, - 0.1){$\bf m_1$}\put(4.1, - 0.1){$\bf m_2$}\multiput(0, 0)(4, 0){2}{\circle*{0.1}} }\put( 0, - 0.1){$\underbrace{ \qquad\qquad\qquad\qquad\qquad \: \: \: \: \: \: }$}\put(1.85, - 0.65){$\bf d$}\end{picture}$

Derivation:

$\sf F \propto m_1 m_2$

$\sf F \propto \dfrac{1}{d^2}$

$\sf F \propto \dfrac{m_1 m_2}{d^2}$

$\sf F = \dfrac{Gm_1 m_2}{d^2}$

Here G is the constant of propotionality and is called universal gravitational constant.