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Two capacitors of capacitance `2 muF` and `3 muF` are joined in series. Outer plate first capacitor is at `1000` volt and outer plate of second capacitor is earthed (grounded). Now the potential on inner plate of each capacitor will beA. `700` VoltB. `200` VoltC. `600` VoltD. `400` Volt |
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Answer» Correct Answer - D Equivalent capacitance `= (2 xx 3)/(2 + 3) = (6)/(5) muF` Total charge by `Q = CV = (6)/(5) xx 100 = 1200 muC` Potential `(V)` across `2 muF` is `V = (Q)/(C ) = (1200)/(2) = 600 V` `:.` Potential on internal plates `= 1000 - 600 = 400 V` |
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