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Two charges each of 6 Coulomb are played 15cm apart from each other in air. Calculate Coulomb's force acting between them. |
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Answer» Answer: Charge on the first sphere, q
=2×10 −7 C Charge on the second sphere, q 2
=3×10 −7 C Distance between the spheres, r=30cm=0.3m F= 4πε 0
r 2
q 1
q 2
Where, ε 0
= Permittivity of free space 4πε 0
1
=9×10 9 Nm 2 C −2
F= (0.3) 2
9×10 9 ×2×10 −7 ×3×10 −7
=6×10 −3 N Hence, FORCE between the TWO small charged spheres is 6×10 −3 N. The charges are of same nature. Hence, force between them will be repulsive. |
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