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Two condenser of capacities `1 muF` and `2 muF` are connected in series and the system is charged to `10` volts. Then the `P.D.` on `1 muF` capacitor (in volts) will beA. `40`B. `60`C. `80`D. `120` |
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Answer» Correct Answer - C Charges developed are same so `C_(1)V_(1) = C_(2)V_(2) rArr (V_(1))/(V_(2)) = 2` `V_(1) + V_(2) = 120 rArr V_(1) = 80` volts |
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