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Two cubes each of volume 74cm³ are joined end to end . find the surface area of resulting cuboids |
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Answer» Answer: 176.3 m² Explanation: to FIND side of cube :- VOLUME of cube = side³ 74 = side³ ∛ 74 = ∛side³ side = ∛ 74; to find dimension of resulting CUBOID :- length of cuboid = ∛ 74 + ∛ 74 = 2∛ 74 width of cuboid = ∛ 74 height of cuboid = ∛ 74 to find surface area of cuboid :- surface area of cuboid = 2(lb + bh + lh) = 2(2∛ 74 × ∛ 74 + ∛ 74 × ∛ 74 + 2∛ 74 ×∛ 74) = 2(2∛ 74*74 + ∛ 74*74 + 2∛ 74*74) = 2(2∛5476 + ∛5476 + 2∛5476) = 2(5∛5426) = 10∛5476 = 10 × 17.63 (approx) = 176.3 m² Thank You :) |
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