1.

Two cubes each of volume 74cm³ are joined end to end . find the surface area of resulting cuboids​

Answer»

Answer:

176.3 m²

Explanation:

to FIND side of cube :-

VOLUME of cube = side³

            74  =  side³  

          ∛ 74  =  ∛side³

          side  =  ∛ 74;

to find dimension of resulting CUBOID :-

length of cuboid = ∛ 74 + ∛ 74

                           =  2∛ 74

width of cuboid = ∛ 74

height of cuboid = ∛ 74

to find surface area of cuboid :-

surface area of cuboid = 2(lb + bh + lh)

                                      = 2(2∛ 74 × ∛ 74 + ∛ 74 × ∛ 74 + 2∛ 74 ×∛ 74)

                                     = 2(2∛ 74*74 + ∛ 74*74 + 2∛ 74*74)

                                     = 2(2∛5476 + ∛5476 + 2∛5476)

                                     = 2(5∛5426)

                                     = 10∛5476

                                     = 10 × 17.63 (approx)

                                     = 176.3 m²

Thank You :)



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