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Two dice are thrown simultaneously. Let A be the event of getting sum less than 4 and B be the event of getting sum not more than 4. Find set “B and not A”.(a) {(1,1), (1,2), (2,1)}(b) {}(c) {(1,1), (1,2), (1,3), (2,1), (2,2), (3,1)}(d) {(1,3), (2,2), (3,1)}This question was addressed to me during an interview for a job.I would like to ask this question from Probability topic in section Probability of Mathematics – Class 11

Answer»

Correct ANSWER is (d) {(1,3), (2,2), (3,1)}

The EXPLANATION is: A = {(1,1), (1,2), (2,1)}

B= {(1,1), (1,2), (1,3), (2,1), (2,2), (3,1)}

“B and not A” CONTAINS elements which are in B but not in A.

So, B and not A = {(1,3), (2,2), (3,1)}.



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