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Two electric bulbs whose resistances are in the ratio 1 : 2 are connected in parallel to a source of constant voltage. What will be the ratio of power dissipation in these wires? |
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Answer» Power \(P=\frac{V^2}{R}\,\infty\,\frac{1}{R}\) for same voltage, the bulbs being in parallel. \(\frac{P_1}{P_2}=\frac{R_2}{R_1}=\frac{2}{1}.\) Thus, ratio of power dissipated is 2 : 1. |
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