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Two electric charges + g and + 4 q are placed at adistanceposition of the point on the line joining the twocharges where the electric field is zero.7.6a apart on a horizontal plane. Find the |
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Answer» For electric field to be zero, elctric field due to +q should be equalto electric field due to +4q. Let us take that point to be at x distance from +q and 6a-x from +4q +q/x²= +4q/ (6a-x)², here 1/4piE0will be cancelled on both sides Taking square roots on both sides we get, 1/x =2/ 6a-x on solving we get, 6a-x = 2x , 6a=3x , x=2a and 6a-x= 4a So, x is at a distance of 2a from +q and 4a from+4q. Hope it helps. thank you for help me |
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