1.

Two equal and like charges when placed 5 cm apan!experience a repulsive force of 0.144 newtons. Themagnitude of the charge in micro-coulomb will be(1) 0.2(2) 2(3) 20(4) 12

Answer»

answer 1 option is right

Let the charge on each object is q Given, separation between them , r = 5cm = 0.05 m force act between them , F = 0.144N [ repulsive force ]

Now, according to Coulombs law, F = Kq²/r² 0.144 = 9 × 10⁹ × q²/(0.05)² 0.016 × (0.05)² × 10⁻⁹ = q² Taking square root both sides, 0.4 × 0.05 × 10⁻⁵ = q q = 0.02 × 10⁻⁵ C = 0.2 × 10⁻⁶ C

Hence, magnitude of each charge = 0.2μC



Discussion

No Comment Found

Related InterviewSolutions