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Two equal unlike charges placed 3 cm apart in air attract each other with a force of 40 N. The magnitude of each charge is |
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Answer» Answer: as we know.... F =k Q q/ r^2 40= k q^2/(0.03)^2 40= 9×10^9 q^2/(0.03)^2 after solving .... we get q=2×10^-5 hope it works PLZ mark it as BRAINLIEST answer |
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