1.

Two equal unlike charges placed 3 cm apart in air attract each other with a force of 40 N. The magnitude of each charge is​

Answer»

Answer:

as we know....

F =k Q q/ r^2

40= k q^2/(0.03)^2

40= 9×10^9 q^2/(0.03)^2

after solving ....

we get q=2×10^-5

hope it works

PLZ mark it as BRAINLIEST answer



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