1.

Two first order reaction have half-life in the ratio `3:2`. Calculate the ratio of time intervals `t_(1):t_(2)`. The time `t_(1)` and `t_(2)` are the time period for `25%` and `75%` completion for the first and second reaction respectively:A. `0.311:1`B. `0.420:1`C. `0.273:1`D. `0.119:1`

Answer» Correct Answer - a
`t_(1)=(2.303xxt_(1//2))/(0.693)"log"(100)/(100-25)` (For I)
`t_(2)=(2.303xxt_(1//2))/(0.693) "log" (100)/(100-75)`, (For II)
`:. t_(1)/t_(2)=3/2xx("log"(100)/(75))/("log"(100)/(25))=3/2xx0.125/0.602`
`= 0.311:1`


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