Two Goats Are Tied With A Rope Of Length 40m Outside Of A Rectangular

1.	Two Goats Are Tied With A Rope Of Length 40m Outside Of A Rectangular Shed Of Dimensions 50m X 30m. The Goats Are Tied To Different Corners Which Lie On The Opposite Ends Of A Diagonal Of The Shed. What Is The Area In Which The Two Goats Can Eat Grass, If They Choose Not To Eat In The Common Aproachable Area?
Answer» Given rope of length = 40m (radius) Area of SEMI circle =(pir^2)/2 = (1600 pi)/2 = 800pi ---(1) Area of quarter circle = (1/2 800 * pi) = 400pi ----- (2) Area of sector is = rr(pi/2)/2 = 25pi ----- (3) By ADDING above eq. (1) (2) & (3) Total area = 1225pi As PER quesiton there are 2 goats so area = 1225pi2 = 2450pi. Given rope of length = 40m (radius) Area of semi circle =(pir^2)/2 = (1600 * pi)/2 = 800pi ---(1) Area of quarter circle = (1/2 800 * pi) = 400pi ----- (2) Area of sector is = rr(pi/2)/2 = 25pi ----- (3) By adding above eq. (1) (2) & (3) Total area = 1225pi As per quesiton there are 2 goats so area = 1225pi*2 = 2450pi.

Two Goats Are Tied With A Rope Of Length 40m Outside Of A Rectangular Shed Of Dimensions 50m X 30m. The Goats Are Tied To Different Corners Which Lie On The Opposite Ends Of A Diagonal Of The Shed. What Is The Area In Which The Two Goats Can Eat Grass, If They Choose Not To Eat In The Common Aproachable Area?

Answer»

Given rope of length = 40m (radius)

Area of SEMI circle =(pi*r^2)/2 = (1600 * pi)/2 = 800*pi ---(1)

Area of quarter circle = (1/2 * 800 * pi) = 400*pi ----- (2)

Area of sector is = r*r*(pi/2)/2 = 25*pi ----- (3)

By ADDING above eq. (1) (2) & (3)

Total area = 1225*pi

As PER quesiton there are 2 goats

so area = 1225*pi*2 = 2450pi.

Given rope of length = 40m (radius)

Area of semi circle =(pi*r^2)/2 = (1600 * pi)/2 = 800*pi ---(1)

Area of quarter circle = (1/2 * 800 * pi) = 400*pi ----- (2)

Area of sector is = r*r*(pi/2)/2 = 25*pi ----- (3)

By adding above eq. (1) (2) & (3)

Total area = 1225*pi

As per quesiton there are 2 goats

so area = 1225*pi*2 = 2450pi.